-10x^2-19x-6=0

Solution for -10x^2-19x-6=0 equation:

-10x^2-19x-6=0

a = -10; b = -19; c = -6;
Δ = b2-4ac
Δ = -192-4·(-10)·(-6)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-11}{2*-10}=\frac{8}{-20}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+11}{2*-10}=\frac{30}{-20}
=-1+1/2
$